Question

$34$ g of hydrogen peroxide is present in $1120$ mL of solution. This solution is called :

• A. $10$ vol solution
• B. $20$ vol solution
• C. $30$ vol solution
• D. $32$ vol solution

Answer 1

The correct option is A $10$ vol solution

Given, mass of $H_2{O}_2$ in one mL $=\frac{34}{1120}$ g
$2H_2{O}_2\to 2H_{2}O+O_2$

Also, $34g{H}_2{O}_2$ gives $16$ g $O_2$ or $11.2$ litres $O_2$ at STP.

$\frac{34}{1120}$ g $H_2{O}_2$gives$\frac{11.2\times 34}{1120\times 34}$ litres $O_2$ $(=0.01$ litres $O_2$ $=10$ ml $O_2)$

So, its a $10$ vol solution.