In an experiment,the readings for the time period of a simple pendulum are 2.63s,2.56s,2.42s,2.71s and 2.80s.Calculate the relative error and the percentage error?

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Solution

mean period of oscillation

$= \frac{2.63 + 2.56 + 2.42 + 2.71 + 2.80}{5} = \frac{13.12}{5} = 2.624 = 2.6$
all the measurement are two to
$2.62 - 2.63 = - 0.01$
$2.62 - 2.56 = + 0.06$
$2.62 - 2.42 = + 0.20$
$2.62 - 2.71 = - 0.09$
Average absolute error
$\frac{0.01 + 0.06 + 0.20 + 0.09 + 0.18}{5} = 0.545 = 0.108 = 0.11 s$

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In an experiment,the readings for the time period of a simple pendulum are 2.63s,2.56s,2.42s,2.71s and 2.80s.Calculate the relative error and the percentage error?

mean period of oscillation=2.63+2.56+2.42+2.71+2.805=13.125=2.624=2.6 all the measurement are two to2.62−2.63=−0.012.62−2.56=+0.062.62−2.42=+0.202.62−2.71=−0.09Average absolute error0.01+0.06+0.20+0.09+0.185=0.545=0.108=0.11s