34. In Triangle ABC, ANGLE BISECTS ANGLE A AND ANGLE C >ANGLE B. PROVE THAT ANGLE ADB>ANGLE ADC

Open in App

Solution

Suggest Corrections

Similar questions

In $△$ ABC, AC $>$ AB and AD bisects $∠$ A. Which of the following option is correct?

Q. AD bisects angle A of triangle ABC, where D lies on BC and angle C is greater than angle B. then angle ADB is greater than angle ADC.

A D

is a median of

△ A B C

. The bisector of

∠ A D B

and

∠ A D C

meet

A B

and

A C

E

and

F

respectively. Prove that

E F | | B C

In the given figure, ABCD is a quadrilateral in which AB = AD and BC = DC. Prove that (i) AC bisects $∠ A a n d ∠ C$ , (ii) BE = DE, (iii) $∠ A B C = ∠ A D C$ .

Q. In the given figure,

∠ B D C = ∠ A D C

and

∠ B C A = ∠ A D B

. Show that : (i)

△ A C D ≅ △ B D C

(ii)

B C = A D

(iii)

∠ A = ∠ B

Join BYJU'S Learning Program