Question

${35.47}^{\circ }$ is equivalent to

• A. ${35}^{\circ }{28}^{\prime }{18}^{\prime \prime }$
• B. ${35}^{\circ }{28}^{\prime }{12}^{\prime \prime }$
• C. ${35}^{\circ }{24}^{\prime }{12}^{\prime \prime }$
• D. ${35}^{\circ }{28}^{\prime }{16}^{\prime \prime }$

Answer 1

The correct option is B ${35}^{\circ }{28}^{\prime }{12}^{\prime \prime }$

${35.47}^{\circ }={35}^{\circ }+{0.47}^{\circ }$
Now,
${0.47}^{\circ }=(0.47\times 60{)}^{\prime }={28.2}^{\prime }={28}^{\prime }+{0.2}^{\prime }$

and ${0.2}^{\prime }=(0.2\times 60{)}^{\prime \prime }={12}^{\prime \prime }$

$\therefore {35.47}^{\circ }={35}^{\circ }{28}^{\prime }{12}^{\prime \prime }$