(35−512)+12 equals
22
30
13
17
We know that (x−y)+z=x−(y−z), for all numbers x, y, z with y>z.
Since the above is true for all the numbers, it must be true for x=35, y=512 and z=12 also, as y=512>12=z
So, (35−512)+12 = 35−(512−12) = 35−5 = 30
[514−25×559+(12+34)] is equal to:
[514− {25×559+(12+34)}] is equal to: