Question

$35mL$ sample of hydrogen peroxide gives of $500mL$ of $O_2$ at ${27}^{\circ }C$ and $1atm$ pressure. Volume strength of $H_2{O}_2$ sample will be

• A. $10volume$
• B. $13volume$
• C. $11volume$
• D. $12volume$

Answer 1

The correct option is B $13volume$

First find volume of oxygen that can be produced at STP.
Given, $V_1=500ml,T_1=300k,T_2=273k$
By using formula,
$\frac{V_1}{T_1}=\frac{V_2}{T_2}$
$T_2=\frac{V_1\times T_2}{T_1}$
$T_2=\frac{500\times 273}{300}=455ml$
$35ml$ can produce $455ml$ of oxygen at STP.
By unitary method,
$\therefore 100ml$ can produce $\frac{1000\times 455}{35}$
$=13000ml=13L$
Option B.