Question

Question 18

$-35\times 107$ is not same as

(a) $-35\times (100+7)$
(b) $(-35)\times 7+(-35)\times 100$
(c) $-35\times 7+100$
(d) $(-30-5)\times 107$

Answer 1

$-35\times 107=-35\times (100+7)=(-35)\times 100+(-35)\times 7$ [using distributive property, i.e.$a\times (b+c)=a\times b+a\times c]$
$=(-35)\times 7+(-35)\times 100$ [as addition is commutative, i.e. a + b = b + a]
Also, $-35\times 107=(-30-5)\times 107[\because (-30-5)=(-35\left)\right]$
Hence, $-35\times 107$ is not same as $-35\times 7+100$.