$350 c m^{3}$ of $C H_{4}$ and $175 c m^{3}$ of an unknown gas $^{'} A^{'}$ diffused in the same time under similar conditions. The molecular mass of gas $^{'} A^{'}$ is:

32

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64

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30

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71

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Solution

The correct option is B $64$
Rate of diffusion is directly proportional to $\frac{1}{\sqrt{molecular mass}}$
$∴ \frac{V o l u m e}{T i m e} \propto \frac{1}{\sqrt{M}}$
$\Rightarrow V o l u m e \propto \frac{1}{\sqrt{M}}$
$\frac{C H_{4} Volume diffused}{Unknown gas volume diffused} = \sqrt{\frac{Unknown gas weight}{C H_{4} gas weight}}$
$\Rightarrow \frac{350}{175} = \sqrt{\frac{Unknown gas weight}{16}}$
Hence, molecular mass is 64 g/mol.

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350cm3 of CH4 and 175cm3 of an unknown gas ′A′ diffused in the same time under similar conditions. The molecular mass of gas ′A′ is:

The correct option is B 64Rate of diffusion is directly proportional to 1√molecular mass∴VolumeTime∝1√M⇒Volume∝1√MCH4Volume diffusedUnknown gas volume diffused=√Unknown gas weightCH4 gas weight⇒350175=√Unknown gas weight16Hence, molecular mass is 64 g/mol.

$350 c m^{3}$ of $C H_{4}$ and $175 c m^{3}$ of an unknown gas $^{'} A^{'}$ diffused in the same time under similar conditions. The molecular mass of gas $^{'} A^{'}$ is: