Question

$36-12xy+y^2$ is a perfect square trinomial

• A. 5
• B. 6

Answer 1

The correct option is A

5

$36-12y+y^2$
= $(6{)}^2-2\times 6\times y+(y{)}^2$
= $a^2-2ab+b^2$ ( taking $6=aandy=b$)
= $(a-b{)}^2$
= $(6-y{)}^2$

Since given trinomial can be expressed as $a^2-2ab+b^2$ , it is perfect square trinomial