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Question

36 g of organic substance is present in one litre of solution at 200 K .
The osmotic pressure of a solution is 1.8×105 Pa .
Calculate the molecular mass of the substance.
Take R=8.3 J mol1 K1


A
332 g mol1
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B
166 g mol1
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C
83 g mol1
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D
154 g mol1
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Solution

The correct option is A 332 g mol1
Osmotic pressure:

π=nV×RT

Here n is number of moles

n=Given massMolar mass=wBmB

V=1 L=103 m3R=8.3 J mol1K1T=200 Kπ=1.8×105 PawB=36 g

πV=wBmB×RTmB=wB×R×Tπ×V

mB=36×8.3×2001.8×105×103mB=332 g mol1

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