36 identical cell each having EMF 1.5 volt and internal resistance 0.5 ohm are connected in series with an external resistance of 12 ohm.8 cells are wrongly connected then current through the circuit will be. A) 1A B) 2A

Open in App

Solution

Dear Student,
$A s t h e s e a r e c o n n e c t e d i n s e r i e s s o t o t a l r e s i s \tan c e = 36 \times . 5 + 12 = 30 o h m a n d t o t a l v o l t a g e i n t h e c i r c u i t = 28 \times 1.5 - 8 \times 1.5 = 30 V s o c u r r e n t i n t h e c i r c u i t = \frac{t o t a l v o l t a g e}{t o t a l r e s i s \tan c e} = \frac{30}{30} = 1 A$
Regard

Suggest Corrections

Similar questions

Q. A student is asked to connected four cells of e.m.f of

1 V

and internal resistance

0.5 o h m

in series with an external resistance of

1 o h m

. But one cell is wrongly connected by him with its terminal reversed. the current in the circuit is

Q. Twelve cells, each having an e.m.f of E volt are connected in series and are kept in a closed box. Some of these cells are wrongly connected with positive and negative terminals reversed. This 12 cell battery is connected in series with an ammeter, an external resistance R ohms and a two-cell battery (two cells of the same type used earlier, connected perfectly in series). The current in the circuit when the 12-cell battery and 2-cell battery aid each other is 3A and is 2A when they oppose each other.

Then the number of cells in 12-cells battery that are connected wrongly is:

Three identical cells, each of 4 V and internal resistance r, are connected in series to a 6 ohm resistor. If the current flowing in the circuit is 2 A. The internal resistance of each cell is

24

cells, each having the same e.m.f. and

2

ohm internal resistance, are used to draw maximum current through an external resistance of

3

ohm. The cells should be connected :

Q. You are provided with

48

cells, each of emf

2

volt and internal resistance

4

ohms. What maximum current can flow in the circuit having an external resistance of

12 Ω

Join BYJU'S Learning Program

36 identical cell each having EMF 1.5 volt and internal resistance 0.5 ohm are connected in series with an external resistance of 12 ohm.8 cells are wrongly connected then current through the circuit will be. A) 1A B) 2A

Dear Student, As these are connected in series so total resistance=36×.5+12=30ohmand total voltage in the circuit=28×1.5-8×1.5=30Vso current in the circuit=total voltagetotal resistance=3030=1A Regard