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Question

36 identical cell each having emf 1.5 volt and internal resistance 0.5Ω are connected in series with an external resistance of 12Ω .If 6 cells are wrongly connected then current through the circuit will be

A
1.2 A
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B
1 A
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C
2 A
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D
4 A
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Solution

The correct option is D 1.2 A
Total resistance in the circuit is, RT=36×0.5+12=30Ω
Net EMF in the circuit is, ET=(306)×1.5=36V

So, current in the circuit is, I=ETRT=3630=1.2A

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