Question

36 identical cell each having emf 1.5 volt and internal resistance $0.5\Omega$ are connected in series with an external resistance of $12\Omega$ .If 6 cells are wrongly connected then current through the circuit will be

• A. 1.2 A
• B. 1 A
• C. 2 A
• D. 4 A

Answer 1

Answer: (A)

1.2 A

Total resistance in the circuit is, $R_T=36\times 0.5+12=30\Omega$

Net EMF in the circuit is, $E_T=(30-6)\times 1.5=36V$

So, current in the circuit is, $I=\frac{E_T}{R_T}=\frac{36}{30}=1.2A$