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Difference of Two Sets

36.Lim log(5+...

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36.Lim log(5+x)-log(5-x)÷ x X-0

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Q. The solution set of

{({log}_{5} x)}^{2} + {log}_{5} x + 1 = \frac{1}{{log}_{5} x - 1}

{l o g}_{5} {l o g}_{5} {l o g}_{2} x = 0

, then the value of

x

{log}_{7} {log}_{5} (\sqrt{x + 5} + \sqrt{x}) = 0

{({log}_{5} x)}^{2} + {log}_{5} x < 2

x

belong to the interval

{log}_{5} \sqrt{7 x - 4} - \frac{1}{2} = {log}_{5} \sqrt{x + 2}

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Difference of Two Sets

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