Question

$36\%$ of the maximum marks are required to pass a test. A student gets $123$ marks and is declared failed by $39$ marks. Find the maximum marks.

Answer 1

Let ${}^{\prime }{x}^{\prime }$ be the maximum marks.

Pass marks $=(123+39)=162$

$36\%$ of maximum marks $=$ Passing marks

Then, $36\%$ of $x=162$

$\Rightarrow \frac{36}{100}\times x=162$

$\Rightarrow x=\frac{162\times 100}{36}=450$

$\therefore$ Maximum marks $=450$