360 g glucose [ $C_{6} H_{12} O_{6}$ ] is given.

a) How many molecules are there in the sample ?

b) What is the total number of atoms in the sample? (Hints: Molecular mass $C_{6} H_{12} O_{6}$ = 180)

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Solution

a) GMM of $C_{6} H_{12} O_{6}$ = 180 g
Number of moles in 360g glucose (n) = $\frac{360 g}{180 g} = 2$
Number of molecules = n $\times N_{A}$
= $2 \times 6.022 \times 10^{23}$
= $12.022 \times 10^{23}$ molecules

b) Total number of atoms
= No of molecules $\times$ Atomicity
= $2 \times 6.022 \times 10^{23} \times 24$
= 289.056 $\times 10^{23}$ atoms
(1 molecule of glucose ( $C_{6} H_{12} O_{6}$ ) contains 24 atoms)

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Similar questions

The molecular formula of glucose is $C_{6} H_{12} O_{6}$ . Calculate its molecular mass. (Atomic masses: C = 12 u; H = 1 u; O = 16 u)

_{6}

_{1}

_{2}

_{6}

(C_{6} H_{12} O_{6})

C_{6} H_{12} O_{6}

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