360 molecules of reactant X is being converted into Y product per hour without any enzyme. By how many times the rate of reaction increases when enzyme A is used in a reaction if 360 molecules of X are being converted per second?

360

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720

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3600

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7200

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Solution

The correct option is C 3600
We know that rate of reaction = Amount of reactant consumed / Time taken

Without enzyme, the rate of reation = 360 molecules per hour.
With enzyme, the rate of reaction = 360 molecules per second.

Therefore, the increase in the rate of reaction with enzyme
= The rate of reaction with enzyme / The rate of reaction without enzyme
= 360 molecules per second / 360 molecules per hour
= $360 \div \frac{360}{60 \times 60} = \frac{360 \times 60 \times 60}{360} = 3600$

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