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Question

36a2−81 can be factorized as ______.


A

(6a+81)(6a81)

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B

(6a9)(36a+9)

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C
(6a+9)(6a9)
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D
(36a+9)(36a9)
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Solution

The correct option is C (6a+9)(6a9)

36a281 is in the form of x2y2.
So, the identity x2y2=(x+y)(xy)
can be used.

36a281=(6a)292=(6a+9)(6a9)


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