37.The distance of the point (3,8,2) from the line (x-1)/2+(y-3)/4+(z-2)/3 measured parallel to the plane 3x+2y-2z +17=0.

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Q. The distance of the point

(3, 8, 2)

from the line

\frac{1}{2} (x - 1) = \frac{1}{4} (y - 3) = \frac{1}{3} (z - 2)

measured parallel to the plane

3 x + 2 y - 2 z + 15 = 0

Q. The distance of the point

P (3, 8, 2)

from the line

\frac{x - 1}{2} = \frac{y - 3}{4} = \frac{z - 2}{3}

measured parallel to the plane

3 x + 2 y - 2 z + 17 = 0

The distance of the point (2, 3, 4) from the plane 3x + 2y + 2z + 5 = 0 measured parallel to the line $\frac{x + 3}{3} = \frac{y - 2}{6} = \frac{z}{2}$ is

Q. The distance of the point (2, 1, – 2) from the line

\frac{x - 1}{2} = \frac{y + 1}{1} = \frac{z - 3}{- 3}

measured parallel to the plane x + 2y + z = 4 is

The distance of the point P (3,8,2) from the line $\frac{1}{2} (x - 1) = \frac{1}{4} (y - 3) = \frac{1}{3} (z - 2)$ measured parallel to the plane $3 x + 2 y - 2 z + 15 = 0 i s$

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