38.Dry air is slowly passed through three solutions of different concentrations c1, c2, c3; each containing non volatile NaCl as solute and water as solvent. if the vessel 2 gain weight and vessel 3 looses weight, then a)c1>c2 b)c1c3

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Dry air is slowly passed through three solutions of different concentrations, C1, C2 and C3 each containing (non-volatile) NaCl as solute and water as solvent, as shown in the fig. If the vessel 2 gains weight and the vessel 3 loses weight, then

Q. Dry air was passed through a beaker solution containing

15 g

of solute and

120 g

of water. Then, it passed through a beaker containing pure water solvent. Loss in weight of the solution beaker was

2 g

and loss in weight of solvent beaker was

0.05 g

. What is the molecular weight of the solute ?

Q. A current of dry air is passed through a solution containing

2.64

g of a non-volatile solute in

30.0

g of ether and then through pure ether. The loss in weight of solution was

0.645

g and of ether was

0.0345

g. The molecular weight of the solid is:

[

M_{e t h e r} = 74 u

]

Q. Dry air is passed through a solution containing 10 g of a solvent in 90 g of water and then through pure water. The loss in weight of the solution is 2.5 g and that of the pure solvent is 0.05 g. Calculate the molecular weight of the solvent.

Q. Consider the following cases A and B in Ostwald-Walker Method:
Case A : Dry air is passed through a pure solvent and then, a dehydrating agent.

Case B: Dry air is passed through a pure solvent and then a solution with non-volatile solute and then, a dehydrating agent

Here,

p^{\circ} is the vapour pressure of the pure solvent

p_{s} is the vapour pressure of the solution

Choose the incorrect option:

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