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Standard XII
Chemistry
Density
38. The effec...
Question
38. The effective radius of iron atom is 1.42 Angstrom. It has rock salt like structure,Calculate its density(Fe=56smu)?
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Similar questions
Q.
The effective radius of the iron atom is
1.42
A
∘
. It has FCC structure. Calculate its density :
[atomic mass of
F
e
=
56
amu]
Q.
The effective radius of an iron atom is
1.42
˚
A
. It has FCC structure. Calculate its density (in g.cm
−
3
) if it is given that the atomic mass of
F
e
is
56
amu.
Q.
If the effective radius of iron (Fe) atom is
141.4
pm which has rock salt type structure, then its density (in g cm
−
3
) will be:
[
F
e
=
56
amu]
Q.
A binary solid
(
A
B
)
has a rock salt structure. If the edge length is
400
pm
and radius of cation is
80
pm
, the radius of anion is:
Q.
The metal nickel crystallizes in a face centred cubic structure. Its density is
8.9
g cm
3
. Calculate (a) the length of the edge of the unit cell and (b) the radius of the nickel atom (in angstrom).
[Given that the atomic weight of Ni is
58.89
amu.]
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