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Byju's Answer
Standard XII
Chemistry
Molarity
380 mL of a g...
Question
380
mL of a gas at
27
0
C
,
800
m
m
of Hg weight
0.455
g. the mol.wt.of gas is:
A
27
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B
28
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C
29
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D
30
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Solution
The correct option is
A
27
volume of 1 mole of gas = 22400 ml
no. of moles in 380 ml of gas =
380
22400
= 0.0169
no. of moles =
g
i
v
e
n
m
a
s
s
m
o
l
e
c
u
l
a
r
m
a
s
s
hence, the molecular mass =
0.455
0.0169
= 27 g
Suggest Corrections
0
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