398 - 16-5-3 - 20-7 9-20

The correct option is C 5(398 ÷ 16.5 + ?^3) ÷ 20=7 9/20⇒ ( 398/16.5+x^3 ) ×1/20=149/20 ⇒ 24.12+x^3=149 ⇒ x^3=124.87 ⇒ x ≈ 5 ...

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398 ÷ 16.5+?3...

Question

$(398 \div 16.5 + ?^{3}) \div 20 = 7 \frac{9}{20}$

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