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Byju's Answer
Standard VIII
Mathematics
Factorisation Using Algebraic Identities
3a-1 2-6a+2=
Question
(
3
a
−
1
)
2
−
6
a
+
2
=
_____
A
(
3
a
−
1
)
(
3
a
−
2
)
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B
(
3
a
−
1
)
(
3
a
+
2
)
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C
3
(
3
a
−
1
)
(
a
−
1
)
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D
(
3
a
−
1
)
(
3
a
+
3
)
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Solution
The correct option is
C
3
(
3
a
−
1
)
(
a
−
1
)
(
3
a
−
1
)
2
−
6
a
+
2
=
(
3
a
−
1
)
2
−
2
(
3
a
−
1
)
=
(
3
a
−
1
)
(
3
a
−
1
−
2
)
=
(
3
a
−
1
)
(
3
a
−
3
)
=
3
(
3
a
−
1
)
(
a
−
1
)
Suggest Corrections
3
Similar questions
Q.
Factorize:
3
a
2
−
1
−
2
a
Q.
Tick (✓) the correct answer:
6a
2
− 13a + 6 = ?
(a) (2a + 3)(3a − 2)
(b) (2a − 3)(3a + 2)
(c) (3a − 2)(2a − 3)
(d) (3a + 1)(2a − 3)
Q.
6
a
2
−
13
a
+
6
=
?
(
a
)
(
2
a
+
3
)
(
3
a
−
2
)
(
b
)
(
2
a
−
3
)
(
3
a
+
2
)
(
c
)
(
3
a
−
2
)
(
2
a
−
3
)
(
d
)
(
3
a
+
1
)
(
2
a
−
3
)
Q.
The sum of
3
expression is
8
+
13
a
+
7
a
2
.
Two of them are
2
a
2
+
3
a
+
2
and
3
a
2
−
4
a
+
1
. Find the third expression.
Q.
The perimeter of a triangle is
8
+
13
a
+
7
a
2
and two of its sides are
2
a
2
+
3
a
+
2
and
3
a
2
−
4
a
−
1
. Find the third side of the triangle.
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