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Question

(3a−1)2−6a+2=_____

A
(3a1)(3a2)
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B
(3a1)(3a+2)
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C
3(3a1)(a1)
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D
(3a1)(3a+3)
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Solution

The correct option is C 3(3a1)(a1)
(3a1)26a+2
=(3a1)22(3a1)
=(3a1)(3a12)
=(3a1)(3a3)
=3(3a1)(a1)

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