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Question

3a−[4a−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯3a−5b−32a−(3a−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯2a−3b)] eqauls


A

a14b

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B

11a14b

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C

5a+14b

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D

a+14b

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Solution

The correct option is B

11a14b


3a[4a¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯3a5b32a(3a¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯2a3b)]

=3a[4a3a+5b32a(3a2a+3b)]

=3a[4a3a+5b32a(a+3b)]

=3a[4a3a+5b32aa3b]

=3a[a+5b6a3a+9b]

=3a[8a+14b]

=3a+8a14b

=11a14b


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