Question

$3A\to 2B$, rate of the reaction $+\frac{d\left[B\right]}{dt}$ is equal to:

• A. $-\frac{3}{2}\frac{d\left[A\right]}{dt}$
• B. $-\frac{2}{3}\frac{d\left[A\right]}{dt}$
• C. $-\frac{1}{3}\frac{d\left[A\right]}{dt}$
• D. $-+2\frac{d\left[A\right]}{dt}$

Answer 1

The correct option is B $-\frac{2}{3}\frac{d\left[A\right]}{dt}$

$3A\to 2B$

Rate$=-\frac{1}{3}\frac{d\left[A\right]}{dt}$ $=+\frac{1}{2}\frac{d\left[B\right]}{dt}$

$\therefore +\frac{d\left[B\right]}{dt}=-\frac{2}{3}\frac{d\left[A\right]}{dt}$

Hence, the correct option is $\text{B}$