#160; #160;3a2 #160; 11ab #160;+ #160;6b2=3a2 #160; 9ab #160; #160;2ab #160;+6b2 #160; #160; #160; #160; #160; #160; #160; # ...

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(x±a)(x±b) = x²±(a+b)x+ab.

3 a2-11 a b+6...

Question

3a² $-$ 11ab + 6b²

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Solution

$3 a^{2} - 11 a b + 6 b^{2} = 3 a^{2} - 9 a b - 2 a b + 6 b^{2} [∵ 3 \times 6 = 18 (- 9) \times (- 2) = 18 and (- 9) + (- 2) = - 11] = 3 a (a - 3 b) - 2 b (a - 3 b) = (a - 3 b) (3 a - 2 b)$

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