#160; #160; #160;3a3 #160; #160;3a= #160;3aa2 #160; #160;1= #160;3aa2 #160; #160;12= #160;3aa #160;+ #160;1a #160; #160;1 ...

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Polynomials

3 a3-3 a

Question

3a³ $-$ 3a

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Solution

$3 a^{3} - 3 a = 3 a (a^{2} - 1) = 3 a (a^{2} - 1^{2}) = 3 a (a + 1) (a - 1)$

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1. (3a-2b)³+ (2b-5c)³+(5c-3a)³

\frac{(a + b)^{3} + (b + c)^{3} + (c + a)^{3} - 3 (a + b) (b + c) (c + a)}{3 (a^{3} + b^{3} + c^{3} - 3 a b c)}

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