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Standard Values of Trigonometric Ratios

3cos2 60o + 2...

Question

$3 c o s^{2} 60^{o} + 2 c o t^{2} 30^{o} - 5 s i n^{2} 45^{o}$ = ?

(a) $\frac{13}{6}$ (a) $\frac{17}{4}$ (c) 1 (d) 4

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Solution

Putting values of respective trigonometric ratios of given angles

$3 open parentheses 1 half close parentheses squared plus 2 open parentheses square root of 3 close parentheses squared minus 5 open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses squared 3 over 4 plus 6 minus 5 over 2 equals 3 over 4 plus 7 over 2 equals fraction numerator 3 plus 14 over denominator 4 end fraction equals 17 over 4 equals a n s w e r$

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Similar questions

Q. (3cos²60° + 2cot²30° − 5sin²45°) = ?
(a)

\frac{13}{6}

\frac{17}{4}

Q. (3cos²60° + 2cot²30° – 5sin²45°) = ?
(a) 1

(b) 4

(c)

\frac{17}{4}

\frac{13}{6}

\frac{2 c o s 60 s i n 60 + c o t 45}{3 c o s^{2} 60 - s i n^{2} 45 + 2 t a n^{2} 30}

Q. Evaluate the following expressions :

2 s i n^{2} 30^{\circ} t a n 60^{\circ} - 3 c o s^{2} 60^{\circ} s e c^{2} 30^{\circ}

Q. Find he value of:

3 {cosec}^{2} 60^{\circ} - 2 {cot}^{2} 30^{\circ} + {sec}^{2} 45^{\circ}

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