Question

3LA=4LB=6LC CALCULATE ALL THE ANGLES OF THE TRIANGLE

Answer 1

In ∆ABC , 3∠A= 4∠B= 6∠C

Let x= 3∠A= 4∠B= 6∠C

X=3∠A
∠A= x/3

X=4∠B
∠B= x/4

X=6∠C
∠C= x/6

By angle sum property

∠A+∠B+∠C= 180°
Put the value of ∠A, ∠B, ∠C
X/3+x/4+x/6= 180°
L.c.m of 3,4,6 = 12

(4x + 3x +2x) /12 = 180°
9x = 12 × 180
X= (12× 180) /9
X= 240°

∠A= x/3
∠A= 240/3 = 80°


∠B= x/4
∠B= 240/4= 60°

∠C= x/6
∠C= 240/6 = 40°