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Types of Redox Reactions

3Mn O 4 2- +4...

Question

$3 M n O_{4}^{2 -} + 4 H^{+} ⟶ M n O_{2} + 2 M n O_{4}^{-} + 2 H_{2} O$
The above reaction is a disproportionation reaction. If true enter 1, else enter 0.

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Solution

$M n O_{4}^{2 -}$ is reduced to $M n O_{2}$ as well as oxidised to $M n O_{4}^{-}$ .
Hence, the reaction is a disproportionation reaction.

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Similar questions

C O_{2}

{M n O}_{4}^{2 -}

3 M n O_{4}^{2 -} + 4 H^{+} \to M n O_{2} + 2 M n O_{4}^{-} + H_{2} O

2 C u^{+}

\to

C u^{2 +}

C u^{0}

3 M n O_{4}^{2 -}

4 H^{+}

\to

2 M n O_{4}^{-}

M n O_{2}

2 H_{2} O

2 K M n O_{4}

△ - \to

K_{2} M n O_{4}

M n O_{2}

O_{2}

2 M n O_{4}^{-}

3 M n^{2 +}

2 H_{2} O

⟶

5 M n O_{2}

4 H^{+}

(a) 2 C u^{+} \to C u^{2 +} + C u (b) 3 M n O_{4}^{2 -} + 4 H^{+} \to 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O (c) 2 K M n O_{4} \to K_{2} M n O_{4} + M n O_{2} + O_{2} (d) 2 M n O_{4}^{-} + 3 M n^{2 +} + 2 H_{2} O \to 5 M n O_{2} + 4 H^{+}

{N H}_{4}^{+} + {N O}_{3}^{-} ⟶ N_{2} O + 2 H_{2} O

2 {C H}_{3} C H O A l {(O E t)}_{3} - ---- \to {C H}_{3} C O O {C H}_{2} {C H}_{3}

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