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Question

(3pq+3qr)218pq2r.


A
9pq2+9qr218p
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B
9p2q+9pr29pq
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C
9p2q2+9q2r2
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D
9p2q2+9qr2+9p
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Solution

The correct option is C 9p2q2+9q2r2

Given: (3pq+3qr)218pq2r

Consider (3pq+3qr)2
Expand this using the identity
((a+b)2=a2+2ab+b2)
(3pq+3qr)2=9(p)2(q)2+9(q)2(r)2+18pq2r

(3pq+3qr)218pq2r=9p2q2+9q2r2+18pq2r18pq2r
=9p2q2+9q2r2


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