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Differentiation to Solve Modified Sum of Binomial Coefficients

3 sin A+4 cos...

Question

3sinA + 4cosA = 5 then what is the value of 4sinA - 3cosA

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Solution

ans is zero

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3 s i n A + 5 c o s A = 5,

(3 c o s A - 5 s i n A)^{2}

3 cos A = 4 sin A;

find the value of:

4 {cos}^{2} A - 3 {sin}^{2} A + 2

3 \frac{m}{25}

3 cos A = 4 sin A

tan A = . . . . . .

4 cot = 3, E v a l u a t e \frac{2 sin A + 3 cos A}{4 sin A - 5 cos A}

3 cos A = 4 sin A

, find the value of :

3 - {cot}^{2} A + c o s e c^{2} A

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Differentiation to Solve Modified Sum of Binomial Coefficients

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