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Question

3tanθ + cotθ = 5 cosec θ, 0θ90. Then the value of θ is __.

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Solution

3sinθcosθ + cosθsinθ = 5sinθ

sinθ ( 3sin2θ + cos2θ) = 5 sinθ cosθ

3(1 - cos2θ) + cos2θ = 5 cosθ

2cos2θ + 5cosθ - 3 = 0

2cosθ [cosθ + 3] - (cosθ + 3) = 0

(cosθ + 3) (2cosθ - 1) = 0

cosθ = -3 or cosθ = 12

not possible as cosθ ≤ 1 θ = 60


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