Question

$3x^2-8x-3=0,x=9,\frac{1}{2},3$

Answer 1

Given equation is :

$3x^2-8x-3=0$
$3x^2-9x+x-3=0$
$(3x+1)(x-3)=0$
$\therefore x=3.\frac{-1}{3}$
Thus, $3$ is the root of the given equation, $9$, $\frac{1}{2}$ are not the roots.