3 x2-8 x-4-04 y2-19 y-12-0A- aB- bC- cD- dE- e

The correct option is B (b) On solving we get x= 2/3 or 2 y= 3/4 or 4 So, clearly, x lt; y ...

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Division of a Polynomial by a Binomial

3 x2+8 x+4=04...

Question

$3 x^{2} + 8 x + 4 = 0$

$4 y^{2} - 19 y + 12 = 0$

(a)

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(b)

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(c)

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(d)

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(e)

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Solution

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Similar questions

3x $^{2}$ + 8x + 4 = 0

4y $^{2}$ - 19y + 12 = 0

$I . x^{2} - 7 x + 12 = 0$
$I I . y^{2} - 12 y + 32 = 0$

x $^{2}$ - 1 = 0

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$I . 3 x^{2} + 8 x + 4 = 0$

$I I . 4 y^{2} - 19 y + 12 = 0$

I. 3 $x^{2}$ + 8x + 4 = 0

II. 4 $y^{2}$ - 19y + 12 = 0

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