3x3+2x2+3x+2=?
(a) (3x−2)(x2−1)
(b) (3x−2)(x2+1)
(c) (3x+2)(x2−1)
(d) (3x+2)(x2+1)
3x3+2x2+3x+2=3x3+3x+2x2+2=3x(x2+1)+2(x2+1)=(3x+2)(x2+1)