$3 x^{3} - 4 x^{2} + 5 x - 6$ (when $x = (- 1)$ )

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Solution

$3 x^{2} - 4 x^{2} + 5 x - 6$ when $x = (- 1)$

$\Rightarrow$ $3 (- 1)^{3} - 4 (- 1)^{2} + 5 (- 1) - 6$

$\Rightarrow$ $3 \times (- 1) - 4 (1) + 5 (- 1) - 6$

$\Rightarrow$ $- 3 - 4 - 5 - 6$

$\Rightarrow$ $- (3 + 4 + 5 + 6)$

$\Rightarrow$ $- 18$

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