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Question

3x+4y=0 , 23y−34x=20
Consider the system of equations above. If (x, y) is the solution to the system, then what is the value of xy?

A
43
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B
34
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C
34
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D
43
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Solution

The correct option is A 43
Given : 3x+4y=0 , 23y34x=20

Multiply the second equation by 4, which will help in eliminating the x - term by adding the equations.

4(23y34)=20×4
83y3x=80
3x+83y=80

Add these two equations, we get


3x+4y=0
3x+83y=80
203y=80
y=3×4
y=12

Now, plug y=12 back into the equation, we get

23y34x=20

231234x=20
34x=208
34x=12
x=16

The solution for the system of equation is (16,12)

The value of xy=43

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