Question

Solve $(3x-5)(2x+3)=0$

Answer 1

Given: $(3x-5)(2x+3)=0$
$\Rightarrow 3x-5=0$ or $2x+3=0$
$\Rightarrow 3x=5$ or $2x=-3$
$x=\frac{5}{3}$ or $x=\frac{-3}{2}$
Hence, $\frac{5}{3}$ and $\frac{-3}{2}$ are the roots of the given equation.