Question

$$\begin{gathered} 3x-5y-19=0, \\ -7x+3y+1=0. \end{gathered}$$

Answer 1

The given system of equation is:
3x − 5y − 19 = 0 .........(i)
−7x + 3y + 1 = 0 ........(ii)

On multiplying (i) by 3 and (ii) by 5, we get:
9x − 15y = 57 or .........(iii)
−35x + 15y = −5 ........(iv)

On adding (iii) from (iv) we get:
−26x = (57 − 5)) = 52
⇒ x = −2

On substituting the value of x = −2 in (i), we get:
−6 − 5y − 19 = 0
⇒ 5y = (− 6 − 19) = −25
⇒ y = −5

Hence, the solution is x = −2 and y = −5.