Question

3^x + x³ + 3³

Answer 1

$$\begin{gathered} \frac{d}{dx}\left(3^x+x^3+3^3\right) \\ =\frac{d}{dx}\left(3^x\right)+\frac{d}{dx}\left(x^3\right)+\frac{d}{dx}\left(3^3\right) \\ =3^x\log 3+3x^2+0 \\ =3^x\log 3+3x^2 \end{gathered}$$