Question

3x + y $-$ $\frac{5}{3}$ = 0

Answer 1

$$\begin{gathered} \mathrm{Given}:3x+y-\frac{5}{3}=0 \\ \Rightarrow 3x+y=\frac{5}{3} \\ \mathrm{Dividing}\mathrm{both}\mathrm{sides}\mathrm{by}\frac{5}{3},\mathrm{we}\mathrm{have}: \\ \frac{(3\times 3)x}{5}+\frac{3y}{5}=\frac{\frac{5}{3}}{\frac{5}{3}} \\ \Rightarrow \frac{x}{{\displaystyle \frac{5}{9}}}+\frac{y}{{\displaystyle \frac{5}{3}}}=1 \\ \therefore x-\mathrm{intercept}=\frac{5}{9};y-\mathrm{intercept}=\frac{5}{3} \end{gathered}$$