Question

$\sqrt{3}{x}^2+2\sqrt{2}x-2\sqrt{3}=0$

Answer 1

Given: $\sqrt{3}{x}^2+2\sqrt{2}x-2\sqrt{3}=0$

On comparing this equation with ax² + bx + c = 0, we get:

$a=\sqrt{3},b=2\sqrt{2}\text{and}c=-2\sqrt{3}$

We know that the discriminant of a quadratic equation, Δ = b² – 4ac.

$\mathrm{On}\mathrm{substituting}a=\sqrt{3},b=2\sqrt{2},c=-2\sqrt{3},\text{we get:}$

Δ = (2$\sqrt{2}$ )² – 4( $\sqrt{3}$) (–2$\sqrt{3}$ )

$\Rightarrow$Δ = 8 + 24 = 32