Question

$3x^2-2\sqrt{6}x+2=0$

Answer 1

$$\begin{gathered} \text{Given:} \\ 3x^2-2\sqrt{6}x+2=0 \\ \text{Here,} \\ a=3,b=-2\sqrt{6}\mathrm{and}c=2 \\ \mathrm{Discriminant}D\mathrm{is}\mathrm{given}\mathrm{by}: \\ D=(b^2-4ac) \\ \text{=}{(-2\sqrt{6})}^2-4\times 3\times 2 \\ \text{= 24}-24 \\ =0 \\ \text{Thus, the roots of the equation are equal}\text{.} \end{gathered}$$