Given: 3x4 – 13x2 + 10 = 0
Let x2 = m. Then, the equation can be written as:
3m2 – 13m + 10 = 0
On splitting the middle term –13m as –3m – 10m, we get:
3m2 – 3m – 10m + 10 = 0
3m(m – 1) –10(m – 1) = 0
(m – 1)(3m – 10) = 0
m – 1 = 0 or 3m – 10 = 0
m = 1 or m =
On substituting m = x2, we get:
x2 = 1 or x2 =
x = ±1 or x = ±
Thus, the solutions of the given equation are ±1, ±