The correct option is B 48y(3y+8)^2=9y^2+2× 3y× 8+64 [Using (a+b)^2=a^2+2ab+b^2] =9y^2+48y+64 ...

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Factorisation Using Algebraic Identities

3 y+82=9 y2++...

Question

$(3 y + 8)^{2} = 9 y^{2} +$ $+ 64$

24 y

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48 y

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12 y

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Solution

The correct option is B $48 y$
$(3 y + 8)^{2} = 9 y^{2} + 2 \times 3 y \times 8 + 64$
[Using $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ ]
$= 9 y^{2} + 48 y + 64$

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