Question

$3y^2-7=\sqrt{3}y$

Answer 1

Given: $3y^2-7=\sqrt{3}y$

On transposing $\sqrt{3}$ y to the left-hand side, we get:

$3y^2-7-\sqrt{3}y=0$

$\Rightarrow 3y^2-\sqrt{3}y-7=0$

On comparing this equation with the general form of the quadratic equation ay² + by + c = 0, we get:
a = 3, b = – $\sqrt{3}$ and c = –7, which are real numbers and a $\ne$ 0.
Thus, the given equation is a quadratic equation in the variable y.