3y² = 8y – 5

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Solution

Given: 3y² = 8y – 5
On transposing all the terms of the right-hand side to the left-hand side, we get:
3y² – 8y + 5 = 0
Thus, the standardised form of the given quadratic equation is 3y² – 8y + 5 = 0.
On comparing this equation with ay² + by + c = 0 in variable y, we get:
a = 3, b = –8 and c = 5

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